Jessore Science and Technology University Admission Circular 2019-20. Jessore Science and Technology University Admission (JUST) Circular 2019-20 has been broadcasted. Starting date of applying in Jessore Science and Technology University Admission Circular 2019-20 was 20th September (Tuesday) 2019 at 12:00 pm. All details information about Jessore Science and Technology University Admission Circular 2019-20 will found in JUST website at www.just.edu.bd &s our website too.
JUST Admission Test Circular 2019-20
Jessore Science and Technology University Admission Circular 2019-20. Jessore Science and Technology University (JUST) Admission Circular for the educational session 2019-20 of 4 years Graduation (Engineering/ Honours) & 5 years B.Pharm (Professional) has declared. Applying time was started on 20th September (Thursday) 2019 at 12:00 pm. Application dead time will be on 19th October (Friday) 2019 at 11:59 pm. Admission test will hold on 22nd November (Wednesday) 2019 & 23th November (Friday) 2018 at several times. JUST Admission test result 2019-20 will be publicized on 25nd November (Sunday) 2019. Orientation will be held on 2nd January (Sunday) 2020. Class will be starting on 2nd January (Sunday) 2020. Concerned candidates have to pay application charge.
Applying Date Start: 15th September (Thursday) 2019 at 12:00 pm
Applying Date Dead: 14th October (Friday) 2019 at 11:59 pm
Admission Test Hold:
Admission test will hold on 21nd & 22rd November 2019
JUST Admission Test Routine 2019
A Unit: 21st November 2019 at 09:30am to 11:00am
B Unit: 21st November 2019 at 12:30pm to 02:00pm
C Unit: 21st November 2019 at 03:30pm to 05:00pm
D Unit: 22nd November 2019 at 09:30am to 11:00am
E Unit: 22nd November 2019 at 12:30pm to 02:00pm
F Unit: 22nd November 2019 at 03:30pm to 05:00pm
Admission Test Result Announce Date: 25th November (Sunday) 2019
Orientation: 2th January ((Sunday) 2020
Class Start: 2th January ((Sunday) 2020
Departments, No. of Seats, and Apply Charge & Educational Requirements
Unit “A” = Both of SSC or similar exam & HSC or similar exam result total CGPA 7.00 & individually minimum CGPA 3.00
Unit “B” = Both of SSC or similar exam & HSC or similar exam result total CGPA 7.00 & individually minimum CGPA 3.00
Unit “C” = Both of SSC or similar exam & HSC or similar exam result total CGPA 6.50 & individually minimum CGPA 3.00
Unit “D” = Both of SSC or similar exam & HSC or similar exam result total CGPA 6.00 & individually minimum CGPA 3.00
Unit “E” = Both of SSC or similar exam & HSC or similar exam result total CGPA 6.00 & individually minimum CGPA 2.50
Unit “F” = Both of SSC or similar exam & HSC or similar exam results total CGPA 6.00 for Science Group, CGPA 6.50 for Commerce Group & CGPA 6.00 for Arts Group & individually minimum CGPA 2.50.
- Unit “A” = 900
- Unit “B” = 800
- Unit “C” = 800
- Unit “D” = 600
- Unit “E” = 600
- Unit “F” = 700
Departments, Unit & No. of seats are given below:-
|Unit||Name of Departments||No. of Seats|
|Unit “A”||Computer Science and Engineering (CSE)||50|
|Chemical Engineering (ChE)||40|
|Petroleum & Mining Engineering (PME)||35|
|Industrial & Production Engineering (IPE)||35|
|Electrical and Electronic Engineering (EEE)||35|
|Unit “B”||Microbiology (MB)||40|
|Genetic engineering & Biotechnology(GEBT)||40|
|Fisheries & Marine Bioscience (FMB)||40|
|Mathematics & Statistics||30|
|Nutrition & Food Technology (NFT)||40|
|Environmental Science & Technology (EST)||45|
|Agro Product Processing Technology (APPT)||30|
|Unit “E”||Physical Education & Sports Science (PESS)||40|
|Unit “F”||BBA in Accounting and Information System (AIS)||40|
Jessore Science & Technology University Admission Notice 2019
Application Procedure of JUST Admission Test 2019-20:
To apply JUST Admission Test Notice 2019-20, concerned candidates ought to apply by SMS process. They must use TeleTalk mobile operator for apply. SMS Process is given below:-
SMS Format: JUST<Space> HSC Board Name <Space> HSC Roll No <Space> HSC Pass Year <Space> SSC Board Name<Space> SSC Roll No<Space> SSC Pass year <Space>Unit name & then send it to 16222.
For an example:
JUST <> CHI <> 675858 <> 2019 <>CHI<> 675747 <> 2017<> F & send to 16222.
JUST Admission Mark Distribution
- Admission test held on MCQ system like other universities.
- Total marks of admission test are 100.
- 80 marks counted for MCQ and rest of 20 counted on the base of HSC and SSC exam GPA.
- SSC exams GPA X 1.9 and HSC GPA X 2= 20
Marks distribution are given below of each unit:
JUST Application Instruction 2019
To Attend JUST Admission Test 2019-20, Candidates have to Fill Up Application Form Online. After Complete Online Application Form, They have to pay Application Fee by Using Dutch Bangla Mobile Banking (Rocket) Payment Method. So, If You Want To Apply For JUST Admission test, Following Below Instruction
Online Form Fill Up Instruction
- Visit The Official Website and Click Admission Menu
- Now Click Under-graduation tab under Admission menu and Click Online Apply
- Now Submit Your SSC & HSC Details. and click Next
- Provide Your Others Information and Upload Photo and Signature
- Select Your Unit Which Group You want to Apply
- Finally, Complete Your Application Form and Collect Your Application Form With Biller ID
How Pay Just Admission Fee:
After Successfully Apply for JUST, Applicant Must have to Complete the Payment Via DBBL Mobile Banking System. To Pay the Admission Test Fee via DBBL Please Follow the Instruction Below.
- Fist Dial *322# from Your Mobile and Press 1.
- Select 1 for Bill Pay Option.
- Enter Biller ID as 254.
- Enter Bill Number which Provide you just, after Online Application. Bill Number Means your Application ID.
- Enter Amount of Your Admission Fees.
- Input Your PIN Number and Complete the Payment.
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